What are some solutions of the equations below? (Quadratic Equation!)

1x^2-3x+1=0

Question

What are some solutions of the equations below? (Quadratic Equation!)

1x^2-3x+1=0

anonymous · Answer

well we need to find what values for x make the left side of the equations equal zero. to do that, you can either factor the equation, or use the quadratic equation.

if there isn't a typo in the equation you gave, then you would have to use the quadratic equation to find the roots

anonymous · Answer

I have the formula written down on a piece of paper...

anonymous · Answer

x = (-b +- sqrt(b^2 - 4ac))/2a

anonymous · Answer

-(b)+ /(6)^2-4(a)(c)

anonymous · Answer

$$x = \frac{ b \pm \sqrt{b^2-4ac}}{ 2a }$$

anonymous · Answer

that's the quadratic formula 
where a = 1
b= - 3
and c = 1

anonymous · Answer

Indeed, lol.

anonymous · Answer

sorry, it's suppose to be - b in front... not positive

anonymous · Answer

Yup

anonymous · Answer

Give me a bit more time...