Question

Find the domain of the function.
Will appreciate an explanation. Thanks in advance.
g(x)=3x/x^2-1

Answer 1

\[g(x)= \frac{ 3x }{ x^2-1 }\]

Answer 2

oh and answer in interval notation.
I got a really weird answer.....

Answer 3

the bottom of fraction cant be 0
so find out what makes this possible and exclude it
bottom of fraction = x^2−1
so we need to make sure that x^2-1 is not equal to 0
so set it equal to zero and solve
x^2-1 = 0
(x-1)(x+1) = 0
when is this true?
when x = 1, or x = -1
so
x CANT be -1 or 1
that's your domain
all real numbers such that x is NOT -1 or 1

Answer 4

hope this helps

Answer 5

got it thanks!

Answer 6

will u come help me when u finish please