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Find the LCM of the following expressions by factorization. 2(x^4-y^4) , 3(x^3+2x^2*y-xy^2-2y^3)
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can you factor the left?
2(x^4-y^4)= 2(x^2-y^2)(x^2+y^2) = 1(x-y)(x+y)(x^2+y^2)
2(x+y)(x-y)(x^2+y^2) and 3(x^2(x+2y)-y^2(x+2y))=3(x+y)(x-y)(x+2y) hence lcm is 6(x+y)(x-y)(x^2+y^2)(x+2y)
guys the answer in book is: 6(x+2y)(x^4-y^4)
thats what i wrote 6 (x^2-y^2)(x^2+y^2)(x+2y) = 6 (x+2y)(x^4-y^4 )
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the book is not simplifying as far as possible
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