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Mathematics 14 Online
OpenStudy (anonymous):

can you show me the steps to this difficult factorising question

OpenStudy (anonymous):

I need to find the possible answers of n 720 = n3 + 3 n2 + 2 n

OpenStudy (anonymous):

*720 = n^3 + 3 n^2 + 2 n

OpenStudy (usukidoll):

take the n out and factor

OpenStudy (anonymous):

if we hv yo find solution we start from 1 and move towards all the factors of 720 gradually putting those values in place of n if n = 8 then we have 720 = 720 hence n = 8 is a solution (n-8)(n^2+11n+90) rest solve n2 + 11n +90 using quadratic formula and find the zeroes

OpenStudy (anonymous):

how do we know about 11

OpenStudy (anonymous):

i am confused

OpenStudy (anonymous):

use the quadratic formula find discriminant have u heard of that formula ??

OpenStudy (anonymous):

no :(

OpenStudy (usukidoll):

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