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can you show me the steps to this difficult factorising question
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I need to find the possible answers of n 720 = n3 + 3 n2 + 2 n
*720 = n^3 + 3 n^2 + 2 n
take the n out and factor
if we hv yo find solution we start from 1 and move towards all the factors of 720 gradually putting those values in place of n if n = 8 then we have 720 = 720 hence n = 8 is a solution (n-8)(n^2+11n+90) rest solve n2 + 11n +90 using quadratic formula and find the zeroes
how do we know about 11
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i am confused
use the quadratic formula find discriminant have u heard of that formula ??
no :(
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