Question

Factor completely: 2x2 + 4x − 2

2(x2 + 2x − 1)

2(x2+ 2)

2x(x2 + 2x − 1)

Prime

Answer 1

2x^2+4x-2

Answer 2

\[2x^{2}+4x-2=2.x^{2}+2.2x-2.1\]
Nw take 2 common from all the expressions @harliedanielfrye

Answer 3

i don't get it

Answer 4

@harliedanielfrye
split the expressions in such a way that they have a common factor
you can write \[2x^{2}=2*x^{2}\]\[4x=2*2x\]\[2=2*1\]

Answer 5

so u can write 2x^2 + 4x − 2=2*x^2+2.2x-2.1 @harliedanielfrye

Answer 6

have u undrstd till here ??? @harliedanielfrye

Answer 7

nope sorry i am really stupid

Answer 8

suppose u need to factorise
x*a+x*b-x*c
u can easily factorise it by writing x(a+b-c)
Here x=2
a=x^2
b=2x
c=1
so
2.x^2+2.2x-2.1
=2(x^2+2x-1)
Have u got it??? @harliedanielfrye

Answer 9

yes

Answer 10

Good :) wtz ur age??? @harliedanielfrye

Answer 11

15

Answer 12

ook :) @harliedanielfrye wch country???

Answer 13

r u asking where am i from?

Answer 14

yep @harliedanielfrye

Answer 15

thx @Curious9876