Factor the algebraic expression below in terms of a single trigonometric function.
csc^2x - 1
its supposd to be in two bionmials. But how?
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OpenStudy (anonymous):
probably not because the answer isnt cot^2x
OpenStudy (anonymous):
so you got cot^2 x answer !
OpenStudy (anonymous):
yeah but its not right
OpenStudy (anonymous):
how do u know ?
OpenStudy (anonymous):
my teacher said so
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OpenStudy (anonymous):
cot^2x
because- if you put csc^2x-1 in terms of sin and cos, you get...
1/(sin^2x)−1
continue putting the numerator in terms of sin and cos...
=(sin^2x+cos^2x)/(sin^2x)−1
=1+(cos^2x)/(sin^2x)−1
The ones cancel out leaving...
cos^2x/sin^2x which simplifies to...
cot^2x
ESSAY FEEDBACK
Hi Amanda, You need to factor these into 2 binomials.
OpenStudy (anonymous):
okay here's the hint the question says two binomials !
OpenStudy (anonymous):
I know :/ I dont get it
OpenStudy (anonymous):
and again it says single trigonometric function !
OpenStudy (anonymous):
... cosx/sinx?
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OpenStudy (anonymous):
add a two in front ov each x
OpenStudy (anonymous):
nope !
OpenStudy (anonymous):
:/
OpenStudy (anonymous):
you'll get cos^2x/ sin^2x
OpenStudy (anonymous):
thats what i said...thats not right?
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OpenStudy (anonymous):
which is binomial but still single and are two !
OpenStudy (anonymous):
huh?
OpenStudy (anonymous):
ur question says one trigonometric function but having two binomial terms
OpenStudy (anonymous):
I dont see how to do it then :/
OpenStudy (anonymous):
there's nothing to do !
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OpenStudy (anonymous):
you already got the answer !
OpenStudy (anonymous):
b..b...but?
OpenStudy (anonymous):
it said it was wrong
OpenStudy (anonymous):
\[\cos^2x/ \sin^2x \]
OpenStudy (anonymous):
oh...so I just had to break it down more?
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