Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in standard form. 8, -14, and 3 + 9i
zeroes of complex types occur in pairs so we hv 3 + 9i and 3-9i also 8 and -14
can u do it now ???
To do this problem, we must realize that complex roots of a polynomial with real coefficients come in conjugates, i.e. in pairs like a+bi and a-bi. So minimally, the polynomial must have the following roots: 8, -14, 3+9i and 3-9i. To construct such a polynomial, we would proceed in writing down the polynomial in factored form, and then expand to get the polynomial in standard form. For example, the polynomial having -2,3, 4-i, 4+i would be written down as: y(x)=(x+2)(x-3)(x-4+i)(x-4-i) which expands to: \(x^4-9x^3+19x^2+31x-102\) NOTE: This is NOT the answer to the given question, just an example.
alright thank you, i was getting a tad confused with what the question was asking.
yw!
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