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given f(2)=1 and the fact that g(x)=-2f(x-1)+5 to find g(3)
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when x=3, we know f(3-1) ....
Sorry I don't understand?
the information provided is rather simple to follow ... f(2) = 1 what is f(3-1) ?
Where did you get f(3-1) ?
Sorry I don't understand?
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g(x) relates to g(3) by letting x=3
since they give you: \[g(x)=2~\color{red}{f(x-1)}+5\] and say to find g(\(\color{orange}3\))
\[g(x)=-2~\color{red}{f(x-1)}+5\] \[g(3)=-2~\color{red}{f(3-1)}+5\] \[g(3)=-2~\color{red}{f(2)}+5\]
they say f(2) = 1 sooo .... \[g(3)=-2~\color{red}{f(2)}+5\] \[g(3)=-2~\color{red}{*1}+5\] \[g(3)=-2+5\]
Ok thank you!
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yep
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