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Mathematics 18 Online
OpenStudy (anonymous):

quick derivation check...

OpenStudy (anonymous):

using equation tool now....

OpenStudy (anonymous):

\[y=Acos3t+Bsin3t\] \[y'=cos3t-3Asin3t+sin3t+3Bcos3t\] \[y''=-3sin3t-3sin3t-9Acos3t+3cos3t+3cos3t-9Bsin3t\]

OpenStudy (anonymous):

I know some terms can be combined but just checking the derivation

OpenStudy (bahrom7893):

Where did that Cos3t in the front come from?

OpenStudy (bahrom7893):

and the Sin3t

OpenStudy (anonymous):

ah they should just be -sin huh I used product rule with the A which is a constant :/

OpenStudy (psymon):

Aren't A and B just constants? These are problems where you are taking guesses, correct? If your guess was simply Acos3t + Bsin3t, then you dont even need product rule. Just -3sin3t + 3cos3t and then -9cos3t - 9sin3t

OpenStudy (bahrom7893):

A and B are just constants, you don't need the product rule there.

OpenStudy (psymon):

Forgot to keep A and B in there, sorry, but still same point.

OpenStudy (bahrom7893):

The only variable is t

OpenStudy (bahrom7893):

(i think)

OpenStudy (anonymous):

so it should be \[y'=-3sin3t+3cos3t\] \[y''=-9cos3t-9sint\]

OpenStudy (psymon):

Bingo, just remembering to keep A and B in there.

OpenStudy (anonymous):

oops -9sin3t

OpenStudy (psymon):

Now you can plug your guess into the D.E and see what ya get.

OpenStudy (anonymous):

ok yeah cause that's what im solving for lol

OpenStudy (psymon):

Figured as much. Been staring at the D.E stuff in prep for my class. Good luck with the question. I have confidence it's the correct guess xD

OpenStudy (anonymous):

@Psymon got the ans! thanks again for helping!

OpenStudy (psymon):

Awesome job ^_^

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