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Find an equation for the horizontal tangent to the curve at P(pi/4, square root of 2). Y = cosx + sinx
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Well, normally we would take the derivative and then put in our x-coordinate to find our slope at that point. When you do this, though, you just get a slope of 0. So this means that there just is a horizontal tangent line at that point, like the question asks. In the end, your equation would then just be y = √(2). If that makes any sense.
It made sense. Thank you for your time. :)
Yep, np :3
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