Question

Jake's band played songs at three different parties. At the first party they played one-fourth as long as they did at the second party, which was one-half as long as the third party. If they played for 7 minutes at the first party, how many minutes did they play at the third party?

three and one-half minutes

fourteen minutes

fifty-six minutes

one hundred twelve minutes

Answer 1

@Mertsj can you help

Answer 2

Let x = minutes played at the third party.
How long did they play at the second party?

Answer 3

@Mertsj im confused

Answer 4

It says at the second party they played half as long as at the third party.

Answer 5

So if they played 10 minutes at the third party, how long did they play at the second party?

Answer 6

@Mertsj um

Answer 7

Now please don't tell me that you don't know what one half of 10 is.

Answer 8

I think I know the answer to the problem its 14.

omg I do lol

Answer 9

@Mertsj or 3 1/2

Answer 10

If they played x minutes at the third party, they played (1/2)x at the second party.

Answer 11

@Mertsj so 3 1/2

Answer 12

If they played (1/2)x minutes at the second party, they played (1/4)(1/2)x at the first party.

Answer 13

(1/4)(1/2)x = (1/8)x

Answer 14

So since we know they played 7 minutes at the first party, we an write:
\[\frac{1}{8}x=7\]

Answer 15

Solve for x

Answer 16

is it 3 1/2 or not?

Answer 17

Or 14

Answer 18

@Mertsj

Answer 19

So you don't know how to solve the equation I posted?

Answer 20

How do you solve this equation:
\[\frac{1}{2}x=5\]