Question

please explain c+(4-3c)+2=

Answer 1

c+4-3c-2=0
-2c+2=0
-2c=-2
c=1
c+(4-3c)-2=0
Add 2 both sides: c+(4-3c)-2+2=2
Simplify -2+2 into 0: c+(4-3c)=2
Switch the order of the 4 and -3c (Commutative Property for Addition): c+(-3c+4)=2


Move the parentheses: [c+(-3c)]+4=2
Add c and -3c: -2c+4=2
Subtract 4 from both sides: -2c+4-4=2-4
Simplify 4-4 and 2-4: -2c=-2
Divide both sides by -2: c=1
Therefore, c=1.

Answer 2

You drop down the c to the 2 understand?

Answer 3

Wait Ha! I messed up don't pay attention to that

Answer 4

Wait ... No I did not. I gived you the answer correct I just made it long

Answer 5

Simplifying
C + (4 + -3c) + -2 = 0

Remove parenthesis around (4 + -3c)
C + 4 + -3c + -2 = 0

Reorder the terms:
4 + -2 + C + -3c = 0

Combine like terms: 4 + -2 = 2
2 + C + -3c = 0

Solving
2 + C + -3c = 0

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + C + -2 + -3c = 0 + -2

Reorder the terms:
2 + -2 + C + -3c = 0 + -2

Combine like terms: 2 + -2 = 0
0 + C + -3c = 0 + -2
C + -3c = 0 + -2

Combine like terms: 0 + -2 = -2
C + -3c = -2

Add '3c' to each side of the equation.
C + -3c + 3c = -2 + 3c

Combine like terms: -3c + 3c = 0
C + 0 = -2 + 3c
C = -2 + 3c

Simplifying
C = -2 + 3c

Answer 6

Is that clearly ?

Answer 7

yes ma'am! thank you so much!

Answer 8

Your very welcome (: