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Mathematics 17 Online
OpenStudy (anonymous):

2sinx*cosx= square root 3* sinx. how do i solve for x? which identities do i use?

OpenStudy (anonymous):

begin by squaring both sides

OpenStudy (lncognlto):

So then 2sinxcosx - sqr3 sinx = 0 so sinx(2cosx-sqr3) = 0 Now solve

OpenStudy (lncognlto):

either sinx = 0 or (2cosx-sqr3) = 0.

OpenStudy (anonymous):

@incognito so i don't use an identity after all? @chandanjha I squared them and got 4(sinxcosx)^2=3sinx^2 I'm trying both of your methods to see which one i understand better :) thank you in advance!

OpenStudy (anonymous):

i think its |dw:1375212310942:dw| so it should be 3 sin x

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