Stable High School has a total of 112 boys and girls who play sports. If the number of boys, b is 16 more than twice the number of girls, g, how many boys play sports at this high school? Which system of equations would help you solve this problem? My answer is b + g = 112 g = 2b + 16 Am I right? :)
shouldnt it be b = 2g+16
yes, it should
number of girls is \(g\), twice the number of girls is \(2g\) and 16 more than that is \(2g+16\)
Yes it should. The reason is because you are adding 16 to the double of the amount of girls (g).
Ok, Thank you! :)
So it should be that one.
No problem :)
that is the number of boys, and so since the total is \(g+2g+16\) which you are told is \(112\) so you can solve via \[g+2g+16=112\]
Thank you so much!! :D
I think that b+g=112 can work because you are adding the total amount of girls and boys to get the sum.
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