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Mathematics 18 Online
OpenStudy (anonymous):

Stable High School has a total of 112 boys and girls who play sports. If the number of boys, b is 16 more than twice the number of girls, g, how many boys play sports at this high school? Which system of equations would help you solve this problem? My answer is b + g = 112 g = 2b + 16 Am I right? :)

OpenStudy (anonymous):

shouldnt it be b = 2g+16

OpenStudy (anonymous):

yes, it should

OpenStudy (anonymous):

number of girls is \(g\), twice the number of girls is \(2g\) and 16 more than that is \(2g+16\)

OpenStudy (calculusxy):

Yes it should. The reason is because you are adding 16 to the double of the amount of girls (g).

OpenStudy (anonymous):

Ok, Thank you! :)

OpenStudy (calculusxy):

So it should be that one.

OpenStudy (calculusxy):

No problem :)

OpenStudy (anonymous):

that is the number of boys, and so since the total is \(g+2g+16\) which you are told is \(112\) so you can solve via \[g+2g+16=112\]

OpenStudy (anonymous):

Thank you so much!! :D

OpenStudy (calculusxy):

I think that b+g=112 can work because you are adding the total amount of girls and boys to get the sum.

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