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Help!!! will give medal:) :)) solve for c and d
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|dw:1375235310676:dw|
Are you allowed to use trig?
im not suree this is geometry
Well \[2^2 = 1^2+d^2\]
Pythagorean theorem, and it's a standard triangle anyways
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so d=1.73
\[\sqrt{3}\]
ooh idk i had to put it that way
Well, sort of. \(d = \sqrt{3}\). This is another eyeball problem. You should know the properties of 30-60-90 right triangles.
so then c=30?
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No. The greater angle is opposite the greater side. c = 60º
ooh ok thanks :)
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