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Mathematics 20 Online
OpenStudy (anonymous):

Help!!! will give medal:) :)) solve for c and d

OpenStudy (anonymous):

|dw:1375235310676:dw|

OpenStudy (anonymous):

Are you allowed to use trig?

OpenStudy (anonymous):

im not suree this is geometry

OpenStudy (anonymous):

Well \[2^2 = 1^2+d^2\]

OpenStudy (anonymous):

Pythagorean theorem, and it's a standard triangle anyways

OpenStudy (anonymous):

so d=1.73

OpenStudy (anonymous):

\[\sqrt{3}\]

OpenStudy (anonymous):

ooh idk i had to put it that way

OpenStudy (tkhunny):

Well, sort of. \(d = \sqrt{3}\). This is another eyeball problem. You should know the properties of 30-60-90 right triangles.

OpenStudy (anonymous):

so then c=30?

OpenStudy (tkhunny):

No. The greater angle is opposite the greater side. c = 60º

OpenStudy (anonymous):

ooh ok thanks :)

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