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C.b? With a decimal?
Okay, making sure.
Well, you would have to do a substitution. So we have 10 = cb^(-1) to start off with. What I did is solve for c by dividing both sides by b^(-1). Once you get your answer for c, you would substitute that value into the 2nd equation of (5/4) = cb^(2).
Yeah, sure. Ill give an example with some different numbers, that way you can try it yourself after :3
|dw:1375240179376:dw| I didnt quite finish the problem, but that would be the process. Youd do the exact same thing with your problem.
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