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Find the derivative of the function. sec q + csc q/csc q. I have the answer but I don't know how to get to it my self, can someone please show me the steps?
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Wait, cscq/cscq? = 1? O.o
Yeah I just figured it cancels out but the answer is dp/dq=sec^2q
Which is only possible if the original function is tanq, since derivative of tanq = sec^2(q)
Well this was a test question and that was the correct answer choice our teacher gave us :/
Isn't the derivative of sec is sec x tan x? Does that have something to do with it?
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Yeah, secx becomes secx tanx. But to have that random csc divided by csc is weird.
lol okay, thanks for trying!
If you're still there I have another derivative questions?
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