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Mathematics 7 Online
OpenStudy (anonymous):

(3x^4y-5)^3 ??

OpenStudy (anonymous):

3x^12 y^3 125

OpenStudy (anonymous):

Is that how it's solved?

OpenStudy (anonymous):

thats the final answer, how it is solved it by multiplying all the exponents by 3

OpenStudy (zzr0ck3r):

not its not

OpenStudy (anonymous):

yes it is.

OpenStudy (anonymous):

okay thank you very much (: do you know how to solve them as well with a root number with exponent?

OpenStudy (zzr0ck3r):

(3x^4y-5)^3 = (3x^4y-5)(3x^4y-5)(3x^4y-5) =

OpenStudy (anonymous):

oh wait...crap you rirght!

OpenStudy (zzr0ck3r):

so you are telling me (2+4)^2 = 2^2 + 4^2

OpenStudy (zzr0ck3r):

yes I am

OpenStudy (anonymous):

i had a brain malfunction

OpenStudy (anonymous):

how would I solve for it?

OpenStudy (anonymous):

like rock said

OpenStudy (zzr0ck3r):

(a+b)^3 = = a^3+3a^2b+3ab^2+b^3

OpenStudy (zzr0ck3r):

for you a = 3x^4y and b = -5

OpenStudy (anonymous):

alrighty thank you(:

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