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laplace transform of (a+bt)^2 where a and b are constants
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@oldrin.bataku i see u typing
same
tbh dont listen to oldrin he's gonna give u wrong answer and u dont want wrong answer considering ur chinese u should even b on here arent u suppose to be smart
ok i just need some example.
$$\mathcal{L}\{(a+bt)^2\}=\mathcal{L}\{a^2+2abt+b^2t^2\}=\frac{a^2}s+\frac{2ab}{s^2}+\frac{2b^2}{s^3}$$
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THT LUK RIGHT
ya thats right epicChoi i just made sure for you you're all good
thanks guys i have another question.
no problem :-) we will help you
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