Question

Help!!! will give medal:):))
solve for I and j

Answer 1

\[\frac{ i }{\sqrt6 }=\tan30^o\]\[\frac{ i }{j }=\sin45^o\]
2 equations - 2 unknows you can solve for both :)

Answer 2

how do I type the first one into a calculator?

Answer 3

im using this calculator http://www.calculator.net/scientific-calculator.html

Answer 4

you check from a table what are the values of trig functions.
\[\tan30^o=\frac{ \sqrt3 }{3 }\]\[\sin45^o=\frac{ \sqrt2 }{2 }\]

Answer 5

so \[i=\frac{ \sqrt6*\sqrt3 }{3 }=\frac{ \sqrt{18} }{3 }=\frac{\sqrt{9*2} }{3 }=\frac{ 3\sqrt2 }{3 }=\sqrt2\]

Answer 6

and
\[\frac{ \sqrt2 }{j }=\frac{ \sqrt2 }{2 }\]
so j=2

Answer 7

the calculator will not give you the exact values

Answer 8

ooh Ok thanks so much for the help :)

Answer 9

yw