see attachment
e)*is cherry
do u have to figure that out for each of the bowls?
i think its two bowls together
that's worse
just put this answer, unless you are blind just grab out whatever flavour you like.
sorry maybe i was wrong, do u mind looking at the pic i just attached
so we have to add both bowls together? is this for an assignment, are you being marked on this?
yeah am being marked.. idk for d, e...
so there are: adding both bowls together: 10 Grape 10 Lemon 10 Cherry 10 Raspberry do you agree?
so each flavour has a 10/40 chance or probability: 25%
meaning that if you want to select a grape and you are blind and cant see, you have a 25% chance of selecting grape, that is not good odds btw.
hey this is for d?
now to workout D: what to do? hmmm
what is the probability of selecting two flavours which are the same?
can it be 1 minus the answer in C
sorry different colours.
answer in c is 0.2150 i was graded and my ans is right
yeah that sound familiar there are formulas for this.
what was your workings for c?
do u know where i can get the formulas? i dont see it in my notes.. working for c:4/20×6/20+5/20×5/20+8/20×2/20+3/20×7/20
ok, so you are half there if you know the answer to c, I get the same thing Now P(different) = 1 - P(same)
okay thanks! so it shud be 0.785... and for e.. is the working like this: first is lemon, 5/20 second is cherry 2/20 both 5/20×2/20 add the first two, subtract the third (5/20+2/20)-(5/20×2/20)=0.325
thanks ybarrap, bambi have you been marked yet, was it right?
@Helpmeplease99 i dont wanna submit yet till im done, because i only have 2 more attempts :(
Here is your tree for probability of color X give Bowl Y: |dw:1375313979171:dw|
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