Can someone check my double angle calculations please? The equation is below
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OpenStudy (anonymous):
\[\sin 2\theta=\frac{ 4 }{ 5 }\]
OpenStudy (anonymous):
my answer is \[\sin \theta=\frac{ 1 }{ \sqrt{5} }\]
OpenStudy (unklerhaukus):
aren't you meant to find theta?
OpenStudy (anonymous):
well yes, but the question asked for Sin theta which is y/r :)
OpenStudy (anonymous):
Looks good assuming that theta is in the is in the first quad. actually it could be positive or negative.
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OpenStudy (anonymous):
Use the half angle identity.
OpenStudy (anonymous):
@Paynesdad i did, but i'm unsure of my work.
OpenStudy (anonymous):
It is correct just include positive or negative.
OpenStudy (anonymous):
Alright! thanks! :)
OpenStudy (anonymous):
@Paynesdad Oh i forgot to mention why my answer was positive.. They told me that 2theta is between pi/2 (90degrees) and Pi (180 degrees) that excludes the negative answer correct?
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OpenStudy (anonymous):
Yes because no theta is between pi/4 and pi/2 and thus in the first quadrant. Good work.