Question

How can I solve a Bernoulli's Equation if the derived "v" is not equal to the original equation?

Ex: y' = 2x-2ycot2x
by multiplying it to y^-1:
y^-1(y') - 2x(y^-1) = -2ycot2x

Am I doin' it right? Please answer. :<

Answer 1

this is not even a Bernoulli equation:$$y'=2x-2y\cot2x\\y'+(2\cot 2x)y=2x$$this is just a linear differential equation.

Answer 2

yeah. my classmates told me too. still, thanks for your answer.