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Identify the period, phase shift and vertical shift of y=-4csc (2x). (if applicable)
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@SavannahWillett
@Psymon ?
Well, whats the normal period of csc?
See I have no clue
Ah. Do you have any idea how to graph a normal csc(x) function?
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no. I'm sorry
Well, let's just ignore that for now then and look at a graph form then, then we can worry about what a secant, cosecant, whatever graph is. So, these graphs have a form of Acsc(Bx - C). If you want the period of a function, you divide the normal period by B. With a csc graph, the period is 2pi. Also, your graph has a B = to 2. So normal period/B = pi, which is your period. As for the phase shift, the phase shiftis C/B. But you have no C in this function, so there is no phase shift. Kinda make sense?
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