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@satellite73 @primeralph
(x-0)^2 + (y-0)^2 = 3^2
is the equation x2 + y2 = r2
Yeah. r =3.
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y is its (x-0)^2?
Because the center is at (0,0).
so what if the center was like ..(2,-3) and the radius was like um 2
(x-2)^2 + (y+3)^2 = 2^2
ooooo ok so its not different
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What?
They're different, depending on the center and radius.
thank you
The final equation is \[x^{2}+y^{2}=3^{2} \]
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