Candy costing $6 per kg is mixed with candy costing $4.50 per kg to produce 112 kg of candy worth $612. How many kg of each type of candy were used?

a)Introduce variables to represents the unknown values
b)Form a system of equation involving the variables
c)Solve the system
d)Answer the problem and check the solution

Question

Candy costing $6 per kg is mixed with candy costing $4.50 per kg to produce 112 kg of candy worth $612. How many kg of each type of candy were used?

a)Introduce variables to represents the unknown values 
b)Form a system of equation involving the variables
c)Solve the system
d)Answer the problem and check the solution

yrelhan4 · Answer

the question already gives you the steps to go about this problem..
any attempts?

anonymous · Answer

i don't understand the question

yrelhan4 · Answer

ok, lets see. what the question actually means is. you have 2 types of candies, candy A and candy B. and to produce a specific type of candy, candy C, you have to mix both of them in specific quantities. you have to find those quantities.

anonymous · Answer

so would the equation be like 6a+4.50b=612?

yrelhan4 · Answer

yup, that would be the first equation.
the second equation would be of the weights. a+b=112..
equate these two and find the values of a and b.

anonymous · Answer

ohh okay thank you!

yrelhan4 · Answer

Cheers.

anonymous · Answer

so i got a=72 and b=40

yrelhan4 · Answer

Thats right. Well done.

anonymous · Answer

yay thanks! :)