Question

3x^4+27x^2 polynomial equation

Answer 1

Take out 3x^2

Answer 2

i have x-0,3,-3

Answer 3

is this correct?

Answer 4

\[3x^2(x^2+9)\]

Answer 5

You have to use the quadratic equation on x^2+9

Answer 6

You will get an imaginary solution.

Answer 7

no you dont either

Answer 8

@dabeezy remember what we did earlier with the i?

Answer 9

um, i have x=0,3,-3
is this correct?

Answer 10

yup

Answer 11

do you homework, thank you but luigio is going help me

Answer 12

\[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 13

You have to use the quad formula, unless you know how to solve without it

Answer 14

dude, its not necessary

Answer 15

um, i have x=0,3,-3

Answer 16

0 is right

Answer 17

by factoring

Answer 18

Let me just ask.
Is the problem
3x^4+27x^2
or
3x^4-27x^2

Answer 19

luigio, is it necessary to check answer aftr solving by factoring?

Answer 20

also its immpossible to use quadratic exuation, its not in ax^2+bx+c+0 form its to the fourth exponent, not squared.....quadratic equation is used when ax^2+bx+c+0 not ax^4+bx+c+0

Answer 21

no neither,
its 3x^4=27x^2 solving a polynomial equation using factoring

Answer 22

I was actually talking about this part.
x^2+9
I got that by factoring out 3x^2
The full equation is
3x^2(x^2+9)

Answer 23

move all non zero numbers to righ to obtain zero on opposing side

Answer 24

Oh I see

Answer 25

You CAN use the quadratic equation on x^2+9

Answer 26

its minus 9

Answer 27

Your answer is correct then, you just had us confused because of that positive

Answer 28

Oh, ok.

Answer 29

because it was + 27, but when u take to other side of equation it becomes negative

Answer 30

but i have 3 seperate answers, is it necessart to check the solutions ?

Answer 31

Tell us how you got that answer.

Answer 32

in some cases will the solutions be false when plugging back in?

Answer 33

ok

Answer 34

It is necessary if you're not sure.

Answer 35

3x^4 = 27x^2
3x^4-27x^2 = 0
3x^2(x^2-9)=0
3x^2=0 x^2-9=0
x^2=0/3 x^2=0+9
x^2=0 x^2=9
sq rt x^2=(+,-)0 sq rt x^2=sq rt 9
x=0 x=(+,-)3
x=0 x=-3 x=3

Answer 36

You are right then.

Answer 37

im suspicious to your answers doyourhomework

Answer 38

If 3x^4 EQUALED 27x^2 in the beginning, your answers are correct.

Answer 39

is 0^4=1?

Answer 40

Here
Plug in x = -3
\[3(-3)^2((-3)^2-9) = 0\]
Plug in x = 3
\[3(3)^2(3^2-9) = 0\]
Plug in x = 0
\[3(0)^2(0^2-9) = 0\]

Answer 41

0^4 = 0

Answer 42

0^2 = 0 ?

Answer 43

Yes.

Answer 44

0^23498237409234 = 0

Answer 45

1^0=? 5^0=?

Answer 46

1

Answer 47

both?

Answer 48

Yes anything to power zero = 1

Answer 49

even an long retriceequation to zero power =1?

Answer 50

(x^2+3x+9)^0? Like this?

Answer 51

that =1?

Answer 52

Yes.

Answer 53

ok will u solve another wit me?

Answer 54

I'll try to.

Answer 55

want me repost?

Answer 56

You can keep it here if you want to. Whatever you want.

Answer 57

Other people can help you if you repost though

Answer 58

Other than me.

Answer 59

u can earn xtra medal

Answer 60

It's ok. You can post here if you want.

Answer 61

I don't care haha.

Answer 62

ok