Question

can anybody please help me with this?

Answer 1

@RH what's your answer?

Answer 2

I was thinking D?

Answer 3

I would have to go with C.) @RH

Answer 4

can you explain? if you don't mind?

Answer 5

Sure. Note that if AD = BA = CB then triangles CDA and CBA are congruent by SSS congruence. Now this also implies that the angle at B must be 90 degrees. We should also note that both triangles are isosceles and so \(\bf \angle DAE=\angle DCE\) and \(\bf \angle BAE=\angle BCE\) . We should also note that \(\bf \angle DAE\) corresponds to \(\bf \angle BAE\) hence \(\bf \angle DAE=\angle BAE\). Then by the transitive property it is implied that \(\bf \angle DAE=\angle DCE=\angle BAE=\angle BCE\). All 4 of these angles must also add up to 180 degrees which means each is 45 degrees. Hence \(\bf \angle DAB=\angle DCB=90\) which means that the polygon is a square since all angles are 90 degrees and all sides are of equal length.

@RH

Answer 6

Do you understand?

Answer 7

YES!!! THANK YOU SO MUCH :)