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The volume of a cone is equal to one third times the area of the base times the height: \[V=\frac{ 1 }{ 3 }Bh\]The base is a circle, whose area is equal to pi times the radius squared, so the volume is: \[V=\frac{ 1 }{ 3 }\pi r^2 h\]So you can plug in the radius and height here and solve for the volume
What did you get when you plugged in?
What happened to your pi? \[V=(1/3)\pi(1^2)(3)\]
But when you simplify you get: \[V=\pi cm^3\]Because the 3 and (1/3) will reduce to 1
No, the 3 will reduce with the 1/3. You'll just be left with pi
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Approximately, yes.
What doesn't make sense about it?
\[V=\frac{ 1 }{ 3 } \pi r^2 h=\frac{ 1 }{ 3 } \pi (1^2) (3)=\frac{ 3 }{ 3 }(1)\pi=(1)(1)\pi=\pi\]
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