MEDAL
A lake was measured with an optical laser ranging instrument as shown in the drawing. Its scale is 1 cm = 1 km.
How wide is the lake?
46.5 m
465 m
4,650 m
46,500 m
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OpenStudy (anonymous):
|dw:1375378342848:dw|
OpenStudy (anonymous):
@Mr.ClayLordMath
OpenStudy (anonymous):
@dpasingh @Hero
OpenStudy (anonymous):
@ash2326
OpenStudy (anonymous):
@Nurali
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OpenStudy (anonymous):
|dw:1375378787411:dw|
OpenStudy (anonymous):
Let BC be the width of the lake
so \[\tan 30^0 = \frac {AB}{BC} \rightarrow \frac{1}{\sqrt{3}} = \frac {4.65}{BC}\]
\[\frac{1}{\sqrt{3}} = \frac {4.65}{BC} \]
\[BC=4.65\sqrt{3} =4.65 \times 1.73 =8.0445 \approx 8\]
Hence width of the lake is 8 KM
OpenStudy (anonymous):
Your ans is not matching with waht i calculated, pls chek the figure properly and then report me.
OpenStudy (anonymous):
mmmm.i think that the answer don't need to have the same value meters have : my answer was option 3
OpenStudy (anonymous):
just see the scale 1cm = 1 km
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OpenStudy (anonymous):
so 1 cm = 1000m
OpenStudy (anonymous):
correct?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
so!!!!
OpenStudy (anonymous):
According to given info the width of the lake must be 8 KM
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OpenStudy (anonymous):
OMG!! we dont have this answer
OpenStudy (anonymous):
I am pretty sure the answer would be 4,650 because since 1cm=1km, you would convert 4,65cm into 4.65km. And 4.65km=4,650m :) hope I helped