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Help please! sin(90-theta)csc theta / cot theta =1
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Use trig identities to transform the left side to the right. Here's the equation in better form...\[\frac{ \sin(90-\theta)\csc \theta }{ \cot \theta }=1 \]
sin(90 - theta) = sin(90)cos(90) + cos(theta)sin(theta) = cos(theta)sin(theta)
I meant a minus sign not plus. -cos(theta)sin(theta)
\[\frac{ (\cos(\Theta)\sin(90)(\sin(\Theta) }{ \cos(\Theta)\sin(\theta) }\]
simplify.
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So... (cos(theta)(sin(theta)/(cos(theta)(sin(theta) and then it all equals 1?
Yes
Thanks! :D
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