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simplify the expression below and write it as a single logarithm: 3log(x+4)-2log(x-7)+5log(x-2)-log(x^2)
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Do you know what to do with exponents?
no could you please explain how to work it out please.
Well whenever there is a number infront of the log, you have to convert it to an exponent like such: \[2logx <=>logx^2\]
oh okay
So can you convert the others?
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yea i think i can, thank you
Remember that: \[loga+logb=\log(a*b)\] \[loga-logb=\log \frac{a}{b}\]
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