Question

i need help with logs
log3 .1+2 log3 x=log3 2+log3 5

Answer 1

Can you retype that using the equation editor?

Answer 2

ok

Answer 3

log3\[\log_{3} .1+2\log_{3} x=\log_{3} 2+\log_{3} 5\]

Answer 4

Well the nice thing is that everything is log base 3. Can you think of any log properties that might help "cancel" out the logs?
Maybe this link will help find one.
http://www.andrews.edu/~calkins/math/webtexts/numb17.htm

Answer 5

one may note that \(\bf \log_{3} .1+2\log_{3} x=\log_{3} 2+\log_{3} 5\\ \implies \log_{3} \cfrac{1}{10}+2\log_{3} x=\log_{3} 2+\log_{3} 5 \)

Answer 6

http://www.chilimath.com/algebra/advanced/log/images/rules%20of%20exponents.gif

apply rule 1 there in the picture