A pebble is tossed from the top of a cliff. The pebble's height in feet is given by y(t) = -16t^2 + 6t + 200, where t is the time in seconds. Its horizontal distance in feet from the base of the cliff is given by d(t) = 5t.

Question

anonymous · Answer

I got 18... School says its not right.

anonymous · Answer

Theres no question here

anonymous · Answer

How far will the pebble be from the base of the cliff when it hits the ground? Round to the nearest foot.  _______ ft

anonymous · Answer

Woops. :P

anonymous · Answer

To start, you'll need to figure out at what time the pebble hits the ground. To figure this out, we'll set the height equal to 0. So:
-16t^2 +6t +200=0
What do you get when you solve for t? You can use factoring or the quadratic formula