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Mathematics 8 Online
OpenStudy (anonymous):

[Part 1: Show all work in simplifying the quantity of three x squared plus three x minus thirty-six, divided by the quantity of x squared minus x minus six Be sure to list restrictions. [Part 2 : Use complete sentences to explain your process.

OpenStudy (anonymous):

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OpenStudy (ankit042):

factorize the numerator and proceed!

OpenStudy (anonymous):

|dw:1375393683581:dw|

OpenStudy (anonymous):

This is where I got stuck

OpenStudy (ankit042):

Factorization of your numerator is not correct. for denominator break it to x^2 -3x+2x -6

OpenStudy (anonymous):

How is it wrong ?

OpenStudy (anonymous):

I thought that you do 3*-36 is -108 then see what two numbers multiply to this and when added equal to 3

OpenStudy (ankit042):

yes the method you mentioned is correct..now just try splitting -108 in two numbers whose sum equals to 3

OpenStudy (anonymous):

12 and -9

OpenStudy (ankit042):

k good now can you proceed?

OpenStudy (anonymous):

umm not sure so then I have (x+12)(x-9)

OpenStudy (anonymous):

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OpenStudy (ankit042):

the next step in factorization is 3x^2 +12x -3x -36 3x(x+4)-3(x+4) (3x-3)(x+4) 3(x-1)(x+4)

OpenStudy (ankit042):

you can try this with denominator to get your answer

OpenStudy (anonymous):

wait you used +12x and -3x why not -9x?

OpenStudy (ankit042):

ohh sry my bad replace it with 9x

OpenStudy (anonymous):

Oh okay thanks ! After that and factorizing the denominator is that how I end the problem or ?

OpenStudy (ankit042):

I think some terms will cancel out and then you will get your answer

OpenStudy (anonymous):

Oh okay great thanks for explaining it!:)

OpenStudy (ankit042):

np :)

OpenStudy (anonymous):

the next step in factorization is 3x^2 +12x -3x -36 3x(x+4)-3(x+4) (3x-3)(x+4) 3(x-1)(x+4)

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