helppp pleaseee
This is an eyeball problem Center: (-3,1) Radius: 4 It's why we have a Standard Form.
show the work please @tkhunny
the equation you have here is standard form of a circle: (x−h)2+(y−k)2=r2 the center point is defined as: (h,k)
That's what "eyeball problem" means. you look at it and write down the answer. If you are familiar with the form, there is no more work. The "work", was getting familiar with it.
o ok @tkhunny
so in your question: \[(x+3)^{2}+(y-1)^{2}=16\] to find (h,k) you will need to make sure it is in the same form as standard form. therefore: (x+3)=(x=(-3) so h=-3 (y-(+1) is already in correct form so: k=1 centerpoint (h,k)= (-3,1)
as for radias: standard form is equal to\[r ^{2}\] so if \[r ^{2}\]=16 then r=\[\sqrt{16}\] which equals 4. radias=4
tkhunny said it, but kind of rudely. once you get more practice with these questions, you will be able to just look at the equation and know the answer. however most professors require you to show your work. i know i typed a lot but it should help! tag me if you need further assisstance!
You cannot show where it was rude. Not everyone agrees, I guess.
guys, I'm the Rude One here , I've worked hard to earn that reputation. So please dont try to take it from me !!
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