Question

What is the equation of the line in slope-intercept form that passes through the point (–2, 4) and is perpendicular to the line y = –2x + 4?

Answer 1

Use the the slope intercept form
y = mx + b

Answer 2

m= slope
b=intercept

Answer 3

The line y = -2x+4 is in slope-intercept form is
-2 = slope
4 = y-intercept

Answer 4

4 = -2(-2) + 4

Answer 5

first we will identify the slope
y = -2x + 4
the slope here is -2.
However, you are looking for a perpendicular line, which means the slope is going to be the negative reciprocal of that slope....to get the negative reciprocal, all you do is " flip " the slope and change the sign. Therefore, the slope of the perpendicular line is negative reciprocal of -2, which is 1/2.
Now we will use the point slope form because we have the points and the slope.
(-2,4) x1 = -2, y1 = 4 slope(m) = 1/2
y - y1 = m(x - x1)
now lets sub our info into the formula..
y - 4 = 1/2(x - (-2)
y - 4 = 1/2(x + 2)
y - 4 = 1/2x + 1
y = 1/2x + 1 + 4
y = 1/2x + 5 <-- this is your equation