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solve by elimination method 2a+4b=12 -2a+b=18
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What do you think the first step should be?
@Avon just add both of the equations 2a+4b=12 -2a+b=18 ---------- What do you get?
gypsy&@uri 4b=6
@gypsy1274
How? +4+1a=5a and 12+18=30
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I mean 5b*
Break it into terms. \(2a-2a\) in the first column
\(4b+b\) in the second column.
i meant 5b=30
yes.
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Now, solve for b.
2a+4b=12 -2a+b=18 ---------- 5b=30 Divide 30 with 5 b=30/5 b=6.
Now you have the value of b now solve for a Put the value of b in eq no(1) 2a+4b=12 2a+4(6)=12 Solve it.
now im lost but would it b 2a+24=12 @uri
2a+24=12 Subract 24 both sides now..
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@uri 2a=12
2a=-12 Now divide -12 with 2
6
-6 ans. so a=-6 and b is 6.
thanks @uri
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