Question

A board game has a spinner with 10 equal sections, numbered 1 through 10. In order to win the game, Mae needs to spin at least a 6 on each of her last two turns. What's the probability of this happening?

Answer 1

my options
1%
10%
25%
36%

Answer 2

i think its 25%

Answer 3

So the change that you'll have a six or higher
there are 10 parts
you can say 1 part is 10% (10*10 = 100%)

Answer 4

what is the probability that she will spin 6 or higher the first spin?

Answer 5

10% ?

Answer 6

how many different numbers will meet the condition?

Answer 7

10

Answer 8

No, she needs to spin 6 or higher
that means 6, 7, 8, 9 and 10 will meet the condition
So 5 numbers.

each part has a 10% change so 5 parts will have 50% change

The first time she spins she has 50% change of getting 6 or higher

Now she needs both spins to end on 6 or higher

So that would be another 50%

What is 50% of 50%?
So the half of 50%

Answer 9

36% ?

Answer 10

no 25 so 25%

Answer 11

That's correct :)
when you divide something by 2, you'll have 50% of the original number
50/2 = 25 so the andwer is 25%

Answer 12

thanks

Answer 13

No problemo ;)