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Y+x2=4x Y+4x=16 Find x and y
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Do you mean: \( Y+x^2=4x \\ Y+4x=16 \\ \) Subtract one equation from the other to get \( Y-Y3+x^2-4x = 4x -16\) Can you take it from here?
Y3 should read Y.
So Y3 is just y
There was a typo, the last line should have read: \( Y-Y+x^2-4x = 4x -16\) which simplifies to: \( x^2-8x+16=0\) which is a quadratic you could solve by factoring. After that, you can evaluate Y from one of the two original equations.
Ohhh okay thank you! :)
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