F(x)=2+x^2 and g(x)=sqrt(x-1) find f(g(x))
\(\bf f(x)=2+x^2\\ g(x)=\color{blue}{\sqrt{x-1}}\\ f(g(x)) = 2+\left(\color{blue}{\sqrt{x-1}}\right)^2 \)
real help is appreciated.
@ehamer2990 what does it mean? does it mean jdoe0001's answer helpless?
to me yes, it is helpless
@jdoe0001 come here to fix it, friend. the asker doesn't want the answer, he wants to know how to solve.
well, so.... \(\bf f(g(x)) = 2+\left(\color{blue}{\sqrt{x-1}}\right)^2\)
anything confusing about it?
\(\bf \left(\sqrt{x-1}\right)^2 \implies \sqrt{(x-1)^2}\)
why on earth are colors involved!?
am I wrong in assuming you're using Internet Explorer? or some older browser?
lol
Im using chrome and I even tried firefox, your formatting was wrong, therefore it didnt show up correctly.
hmmm? i shows up in firefox and chrome just fine :/
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