Question

i need help with the file i add
pl look at it help me
I WILL AWARD MEDAL!!!!

Answer 1

i need help with the file i add
pl look at it help me
I WILL AWARD MEDAL!!!!

Answer 2

i need help with the file i add
pl look at it help me
I WILL AWARD MEDAL!!!!

Answer 3

You want to find the equation for a line that passes through the two points:
(1996,173) and (2002,215).
First of all, remember what the equation of a line is:

y = mx+b
Where:
m is the slope, and
b is the y-intercept

First, let's find what m is, the slope of the line...
So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (1996,173), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=1996 and y1=173.
Also, let's call the second point you gave, (2002,215), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=2002 and y2=215.

Now, just plug the numbers into the formula for m above, like this:

m= \[\frac{ 215-173 }{ 2002 -1996 } \]

or...

m= 42 / 6

or...

m=7

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=7x+b
Now, what about b, the y-intercept?
To find b, think about what your (x,y) points mean:
(1996,173). When x of the line is 1996, y of the line must be 173.
(2002,215). When x of the line is 2002, y of the line must be 215.

Because you said the line passes through each one of these two points, right?
Now, look at our line's equation so far: y=7x+b. b is what we want, the 7 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (1996,173) and (2002,215).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(1996,173). y=mx+b or 173=7 × 1996+b, or solving for b: b=173-(7)(1996). b=-13799.
(2002,215). y=mx+b or 215=7 × 2002+b, or solving for b: b=215-(7)(2002). b=-13799.

See! In both cases we got the same value for b. And this completes our problem.
The equation of the line that passes through the points
(1996,173) and (2002,215)

is

y=7x-13799

Answer 4

(b) use the line to estimate the population in 2003.
the populationin 2003 is estimate to be _____ thousand nmates.

Answer 5

Set x = to 2003 in the equation we found.

y = 7 ( 2003) - 13799
y= 222

Answer 6

try got it not it

Answer 7

Do they want point form? (2003,222)?

Answer 8

how did you add the file?

Answer 9

attach fflie it by draw

Answer 10

MichaelBoocher no
im lost

Answer 11

Screen.
Maybe 222,000?

Answer 12

look at got and see what you think

Answer 13

2013 BRO!

Answer 14

292 i got a red x

Answer 15

http://www.wolframalpha.com/input/?i=y%3D+7x+-+13799+%2C+x+%3D+2013

I dont know what to say... its the answer.