Question

If 9a^2-b^2=0 and ab<0, then (a-b)/(a+b)=?

Answer 1

This might help somewhat...\[\Large 9a^2-b^2= (3a)^2 - b^2\]Notice this is a difference of two squares.

Answer 2

what do you mean? i cannot understand

Answer 3

use x ^2 - y ^2 = (x+y)(x-y)

Answer 4

i know, but how about the next step

Answer 5

i think u hv got x = 3a and y = b

Answer 6

yes

Answer 7

\[\Large (3a)^2 - b^2 = (3a + b)(3a - b) = 0\]

Answer 8

just equate them to 0

Answer 9

b=3a?

Answer 10

-1/2 ?

Answer 11

but ab <0
so b not = 3a

Answer 12

ohh..

Answer 13

b=-3a

Answer 14

u hv to equate the other one 3a+b = 0

Answer 15

yeah just replace b with -3a

Answer 16

what did u get ??

Answer 17

-2

Answer 18

gr8

Answer 19

well done

Answer 20

thx:)