Solve 5^x + 5 = 9^x anyone help please :(
first u subtract 9x-5x then u should get 5=4x then u divide and u get 5/4=x
x ≈ –3.63 x ≈ –0.28 x ≈ 0.07 x ≈ 13.69 those are my answers
r u sure it has to be one of those?
positive it is solving exponential equations with unequal bases
omg im so sorry I wrote the question wrong it is 5^x+5=9^x
oh now it makes sense lol. ok let me try again
it is \[\large 5^{x+5}=9^x\] maybe ?
yes that's it
then start with \[(x+5)\ln(5)=x\ln(9)\] and do some algebra to solve for \(x\)
don't be confused by the \(\ln(5)\) and \(\ln(9)\), they are just numbers
im so confused could you help me out
multiply out and get \[x\ln(5)+5\ln(5)=x\ln(9)\] subtract \(x\ln(5)\) and get \[5\ln(5)=x\ln(9)-5\ln(5)\] factor out the \(x\) for \[5\ln(5)=(\ln(9)-\ln(5))x\] and finally divide to get \[\frac{5\ln(5)}{\ln(9)-\ln(5)}=x\]
i understand what you did but i don't understand the concept of ln
so i wouldn't know how to divide that :(
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