Question

If the perimeter of an isosceles trapezoid is 59.9 meters, and the bases measure 23.2 meters and 17.1 meters, find the length of the legs of the trapezoid.

Answer 1

so the perimeter is = 59,9 m

and you know that you get the perimeter adding these two bases and the legs of the equale sides

so the sum of bases is equale 23,2 + 17,1 = 40,3 m

the legs of the equale sides let being 2x

the perimeter = 59,9

so subtracting from the perimeter the sum of the bases you will get the sum of the equale sides so

59,9 - 40,3 = 19,6

than you know that 2x=19,6

so x = 19,6/2 = 9,8 m

than you get that the legs of the equale sides is equal 9,8 m

hope so much that is understandably sure right easy

good luck

bye