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Using the given zero, find one other zero of f(x). 4 - 5i is a zero of f(x).= x^4 - 8x^3 + 42x^2 - 8x + 41.
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one zero is \(4-5i\) so the other zero must be the conjugate \(4+5i\) now we can figure out what that polynomial must be fairly easily
Oh okay so it's just the conjugate. Thank you.
one way is to work backwards \[x=4-5i\\x-4=-5i\\(x-4)^2=-25\\x^2-8x=-25\\x^2-8x+25=0\]
oh you only have to find ONE other zero? then it is really easy, just the conjugate i thought you had to find all of them!
helps if i would read the question ....
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