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Mathematics 19 Online
OpenStudy (anonymous):

Find a fourth degree polynomial function with real coefficients that has 2, -2 and -3i as zeros.

OpenStudy (anonymous):

+3i is the other zero so f(x)=(x-2)(x+2)(x+3i)(x-3i)

OpenStudy (anonymous):

The opposite of an imaginary number is always another zero

OpenStudy (anonymous):

thank you!

OpenStudy (anonymous):

would you help me write this in standard form? f(x) = -2x2+ 8x- 5

OpenStudy (anonymous):

I don't understand standard form

OpenStudy (anonymous):

@TheDoctorRules

OpenStudy (anonymous):

That is already in standard form for a quadratic equation

OpenStudy (anonymous):

oh really?!

OpenStudy (anonymous):

wow. okay. well thanks so much

OpenStudy (anonymous):

Youre welcome :)

OpenStudy (anonymous):

The standard form for a quadratic equation is ax2 + bx + c = 0

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