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Mathematics 15 Online
OpenStudy (anonymous):

factor completely: see below:

OpenStudy (anonymous):

\[2m ^{2}-4m ^{5}n ^{8}-48mn ^{9}\]

OpenStudy (anonymous):

I am confused?

OpenStudy (anonymous):

how did they get this as an answer???????\[2m(m-2m ^{4}n ^{8}-24n ^{9}\]

OpenStudy (anonymous):

I got this \[2(m ^{2}-2m ^{5}n ^{8}-24mn ^{9})\]

OpenStudy (anonymous):

ok

OpenStudy (zzr0ck3r):

well they just factor a 2m out of everything \[2m(m-2m^4n^8-24n^9)\]

OpenStudy (zzr0ck3r):

I don't know how to finish it

OpenStudy (mathstudent55):

@zzr0ck3r You finished it. That's all you can do.

OpenStudy (zzr0ck3r):

how do we know that @mathstudent55 ?

OpenStudy (mathstudent55):

\(-2m(2m^4n^8 - m + 24n^9)\) There are no two integers whose product is 2*24=48 and whose sum is -1.

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