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How would I simplify the square root 98 times x to the fifth power.
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umm all u gotta do is find \[\sqrt{98}\]
which is 2times 49 and 49 equals 7 times 7 so the equation is 7\[\sqrt{2}\]
\[7\]
\[7\sqrt{2}\]
so 7x^5 radical 2 is answer
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I have 7x^2 radical 2 as a choice, should I do that one?:o
how because \[7\sqrt{2}timesx ^{5}is basically 7x ^{5}\]
radical 2
I don't know, it's just the closest answer choice to what you said.
i mean when u multiplay x^5 and radical 98 u just find radical 98 which is 7 radical 2 and u just add x^5 to 7 which is 7x^5radical 2
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when its 2x^5 times 7 than itll be 14x^5
as in example
Alright, thanks!
np
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