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Using the image below, find the point that divides the line segment AB into a ratio of 2:3.
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The point of division 2/3 is given by: xm=xa+(xb-xa)*2/3 ym=ya+(yb-ya)*2/3
From the diagram, the coordinates of A are (-4,6), so xa=-4, ya=6. B(5,1), so xb=5, yb=1. The formula I gave is the standard point of division formula, where xm, ym are the x- and y-coordinates of the required point which divides AB in ratio 2/3. Oops, the formulas should read: xm=xa+(xb-xa)*2/5 ym=ya+(yb-ya)*2/5 because 5=2+3|dw:1375667906528:dw|
So is my answer (0.5, 3.5) ?
@mathmate
not quite, but close. Did you do xm=-4+(5-(-4))*2/5 ym=6+(1-6)*2/5 or did you use a different formula?
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